| Re: Math Question #1 [message #357820 is a reply to message #357817] |
Sun, 09 November 2008 09:23   |
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archerman
Messages: 348
Registered: May 2007
Location: Istanbul / Turkey
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| CarrierII wrote on Sun, 09 November 2008 17:32 |
If Y = Sin(5X) / 2 - 2 * Cos(2X)
then as X -> 0, Y -> infinity.
If X = 0 then
Sin(5X) = Sin(0) = 0.
2 - 2Cos(2*0) = 2 - 2Cos(0) = 2 - 2(1) = 0. - Can't divide by zero!
Thus if X is almost 0, we have
Sin(5X) / 2 - 2Cos(~0) which is
Sin(5X) / 2 - 2*(~1) which is
Some number / Some other number < 1 and close to 0. This causes the whole expression to increase in value because you're dividing by a fraction.
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maybe i didnt understand, but how would you know that the numerator increases more as the denominator increases less? maybe the numerator is a fraction too. sin5x is the closest to zero, and 2-2cosx is the closest to zero as well because 2-2cosx=2-2*1=~0. so its still 0/0.
sorry for my English
[Updated on: Sun, 09 November 2008 09:25] Report message to a moderator |
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